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Simple question - end a raw string with a single backslash ?

Op 13/10/20 om 15:14 schreef Serhiy Storchaka:
> 13.10.20 11:52, Tony Flury via Python-list ????:
>> I am trying to write a simple expression to build a raw string that ends
>> in a single backslash. My understanding is that a raw string should
>> ignore attempts at escaping characters but I get this :
>>  ??? >>> a = r'end\'
>>  ??? ? File "<stdin>", line 1
>>  ??? ??? a = r'end\'
>>  ??? ????????????? ^
>>  ?? SyntaxError: EOL while scanning string literal
>> I interpret this as meaning that the \' is actually being interpreted as
>> a literal quote - is that a bug ?
> r'You can\'t end raw string literal with a single "\"'
> If backslash be true inner in a raw string, the above literal would end
> after \'. It would be very hard to write a raw string containing both \'
> and \", and even \''' and \""" (there are such strings in the stdlib).
> So you have problem either with trailing backslash, or with inner
> backslash followed by quotes. Both problems cannot be solved at the same
> time. Python parser works as it works because initially it was easier to
> implement, and now this cannot be changed because it would break some
> amount of correct code.

IMO the way python does this is broken.

 >>> st=r'You can\'t end raw string literal with a single "\"'
 >>> print(st)

Now either the \ is special or it is not.

1) If it is special, it should change how the ' is treated but not 
appear itself.

2) If it is not special, it should just appear and not change how the ' 
is treated.

What python does here is a combination of both. The \ appears and it
changes how the ' is treated. That is IMO broken.

Antoon Pardon.