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Parisa Ch wrote: > x=np.linspace(0,2*math.pi,n) > n=len(x) > r=int(math.ceil(f*n)) > h=[np.sort(np.abs(x-x[i]))[r] for i in range(n)] > > this is part of a python code. the last line is confusing? x is a matrix > and x[i] is a number. how calculate x-x[i] for each i? > why the put r in [] ? Brake it appart: y = x - x[i] # the numpy feature that makes that possible is called # "broadcasting" subtracts the value x[i] from every entry in the vector x z = np.abs(y) calculates the absolute value of every entry in y. t = np.sort(z) sorts the values in z and finally, assuming r is an integer, u = t[r] looks up a single scalar in the vector. The enclosing "list comprehension" [expr for item in iterable] builds a list of n values calculated as sketched above.

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